Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
kas | 756 | 37 | 1 | 37.0000 |
bet | 493 | 21 | 1 | 21.0000 |
lai | 218 | 9 | 1 | 9.0000 |
kur | 132 | 9 | 1 | 9.0000 |
Pasaules | 73 | 8 | 2 | 4.0000 |
parasti | 115 | 4 | 1 | 4.0000 |
centrs | 44 | 4 | 1 | 4.0000 |
1. | 59 | 4 | 1 | 4.0000 |
ka | 226 | 4 | 1 | 4.0000 |
krastos | 19 | 3 | 1 | 3.0000 |
mm | 98 | 6 | 2 | 3.0000 |
iela | 29 | 3 | 1 | 3.0000 |
tomēr | 68 | 3 | 1 | 3.0000 |
nosaukumu | 43 | 3 | 1 | 3.0000 |
Rīgā | 54 | 3 | 1 | 3.0000 |
māja | 20 | 3 | 1 | 3.0000 |
jo | 104 | 3 | 1 | 3.0000 |
sporta | 40 | 3 | 1 | 3.0000 |
kad | 140 | 6 | 2 | 3.0000 |
vidēji | 32 | 3 | 1 | 3.0000 |
Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
laiku | 66 | 1 | 8 | 0.1250 |
aprīlī | 31 | 1 | 5 | 0.2000 |
pat | 76 | 1 | 5 | 0.2000 |
iespējams | 39 | 1 | 4 | 0.2500 |
olimpiskajās | 30 | 1 | 4 | 0.2500 |
novembrī | 39 | 1 | 4 | 0.2500 |
vairākas | 82 | 1 | 4 | 0.2500 |
kopš | 54 | 1 | 4 | 0.2500 |
gadsimtā | 32 | 1 | 4 | 0.2500 |
7 | 40 | 1 | 4 | 0.2500 |
gaitā | 40 | 1 | 4 | 0.2500 |
kļuva | 150 | 2 | 7 | 0.2857 |
beigām | 73 | 2 | 7 | 0.2857 |
nav | 173 | 3 | 10 | 0.3000 |
vēlāk | 107 | 2 | 6 | 0.3333 |
janvārī | 32 | 1 | 3 | 0.3333 |
decembrī | 36 | 1 | 3 | 0.3333 |
200 | 19 | 1 | 3 | 0.3333 |
diviem | 31 | 1 | 3 | 0.3333 |
kuriem | 36 | 1 | 3 | 0.3333 |
In this subsection, we compute the ratio of the number of right neighbors and the number of left neighbors. Again, we look for words with extreme ratios:
Data for first table:
select word,w.freq,aa.cnt, bb.cnt,aa.cnt/bb.cnt as r from words w, (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where w_id=aa.w1_id and aa.w1_id=bb.w2_id order by r desc limit 20;
Diagram data:
select aa.cnt, bb.cnt from (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where aa.w1_id=bb.w2_id;
5.1.7.1 Number of NN co-occurrences vs. Frequency I
5.1.7.2 Number of NN co-occurrences vs. Frequency II